1: A 5 9

2: 2 6 7

3: 3 4 8 ]]>

As another listener wrote:

* Pile x beats Pile ((x +1) mod 3) + 1, five out of nine times.*

So the second player should take from the pile before, below, or the the left of the first player.

Didn’t you say it the other way around?

*Thanks for the show. I wouldn’t have memorized the trick if you had gotten it exactly right. *

The 3 piles that you gave were as follows:

1: A 6 8

2: 3 5 7

3: 2 4 9

So when I pick from the first pile and you pick from the second pile here are the possible outcomes:

A 3 – You Win

A 5 – You Win

A 7 – You Win

6 3

6 5

6 7 – You Win

8 3

8 5

8 7

So you win only 4 out of 9 times

When I pick from the second pile and you pick from the third pile here are the possible outcomes:

3 2

3 4 – You Win

3 9 – You Win

5 2

5 4

5 9 – You Win

7 2

7 4

7 9 – You Win

So you win only 4 out of 9 times again

When I pick from the third pile and you pick from the first pile here are the possible outcomes:

2 A

2 6 – You Win

2 8 – You Win

4 A

4 6 – You Win

4 8 – You Win

9 A

9 6

9 8

So you win only 4 out of 9 times again

So it seems that the piles should have been in the opposite order

1: 2 4 9

2: 3 5 7

3: A 6 8

Am I missing something?

Thanks!

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