Comments on: CI. The Royal Order of the Garter http://mathfactor.uark.edu/2007/04/23/ci-the-royal-order-of-the-garter/ The Math Factor Podcast Site Tue, 07 Oct 2008 18:08:01 +0000 http://wordpress.org/?v=2.5.1 By: strauss http://mathfactor.uark.edu/2007/04/23/ci-the-royal-order-of-the-garter/#comment-63 strauss Tue, 01 May 2007 15:24:21 +0000 http://mathfactor.uark.edu/2007/04/23/ci-the-royal-order-of-the-garter/#comment-63 This seemed far too vulgar to ask Lord Butler! But we were wondering too. In general, though the more frequently members are replaced, the easier the job-- if all the members were replaced each year, for example, no one would ever sit next to the same person twice. This seemed far too vulgar to ask Lord Butler!

But we were wondering too.

In general, though the more frequently members are replaced, the easier the job– if all the members were replaced each year, for example, no one would ever sit next to the same person twice.

]]> By: jaquish http://mathfactor.uark.edu/2007/04/23/ci-the-royal-order-of-the-garter/#comment-62 jaquish Tue, 01 May 2007 15:06:56 +0000 http://mathfactor.uark.edu/2007/04/23/ci-the-royal-order-of-the-garter/#comment-62 How do you account for members who die and are replaced by new members? How do you account for members who die and are replaced by new members?

]]> By: rmjarvis http://mathfactor.uark.edu/2007/04/23/ci-the-royal-order-of-the-garter/#comment-60 rmjarvis Tue, 01 May 2007 03:48:11 +0000 http://mathfactor.uark.edu/2007/04/23/ci-the-royal-order-of-the-garter/#comment-60 For those who don't believe the solution given in the show, here it is spelled out for 12 years in a row. Feel free to spot check any of the people to confirm that they sit next to all 24 other people. Pretty cool. ABCDEFGHIJKLMNOPQRSTUVWXY ADBFCHEJGLINKPMROTQVSXUYW AFDHBJCLENGPIRKTMVOXQYSWU AHFJDLBNCPERGTIVKXMYOWQUS AJHLFNDPBRCTEVGXIYKWMUOSQ ALJNHPFRDTBVCXEYGWIUKSMQO ANLPJRHTFVDXBYCWEUGSIQKOM APNRLTJVHXFYDWBUCSEQGOIMK ARPTNVLXJYHWFUDSBQCOEMGKI ATRVPXNYLWJUHSFQDOBMCKEIG AVTXRYPWNULSJQHOFMDKBICGE AXVYTWRUPSNQLOJMHKFIDGBEC For those who don’t believe the solution given in the show, here it is spelled out for 12 years in a row. Feel free to spot check any of the people to confirm that they sit next to all 24 other people. Pretty cool.

ABCDEFGHIJKLMNOPQRSTUVWXY
ADBFCHEJGLINKPMROTQVSXUYW
AFDHBJCLENGPIRKTMVOXQYSWU
AHFJDLBNCPERGTIVKXMYOWQUS
AJHLFNDPBRCTEVGXIYKWMUOSQ
ALJNHPFRDTBVCXEYGWIUKSMQO
ANLPJRHTFVDXBYCWEUGSIQKOM
APNRLTJVHXFYDWBUCSEQGOIMK
ARPTNVLXJYHWFUDSBQCOEMGKI
ATRVPXNYLWJUHSFQDOBMCKEIG
AVTXRYPWNULSJQHOFMDKBICGE
AXVYTWRUPSNQLOJMHKFIDGBEC

]]> By: strauss http://mathfactor.uark.edu/2007/04/23/ci-the-royal-order-of-the-garter/#comment-58 strauss Tue, 24 Apr 2007 14:19:57 +0000 http://mathfactor.uark.edu/2007/04/23/ci-the-royal-order-of-the-garter/#comment-58 Uh oh! We stated that if there were 8 members of the order, only two years could pass before some pair would again have to sit next to one another. But, alas, this is not the case! Consider A B C D E F G H A D B G C F H E A F B E C H D G <em> So what's the answer to the puzzle?</em> Uh oh! We stated that if there were 8 members of the order, only two years could pass before some pair would again have to sit next to one another. But, alas, this is not the case!

Consider

A B C D E F G H

A D B G C F H E

A F B E C H D G

So what’s the answer to the puzzle?

]]>