<?xml version="1.0" encoding="UTF-8"?><rss version="2.0"
	xmlns:content="http://purl.org/rss/1.0/modules/content/"
	xmlns:dc="http://purl.org/dc/elements/1.1/"
	xmlns:atom="http://www.w3.org/2005/Atom"
	xmlns:sy="http://purl.org/rss/1.0/modules/syndication/"
	xmlns:itunes="http://www.itunes.com/dtds/podcast-1.0.dtd"
	xmlns:media="http://search.yahoo.com/mrss/"
	>
<channel>
	<title>Comments on: Follow Up: The Harmonic Series</title>
	<atom:link href="http://mathfactor.uark.edu/2008/08/follow-up-the-harmonic-series/feed/" rel="self" type="application/rss+xml" />
	<link>http://mathfactor.uark.edu/2008/08/follow-up-the-harmonic-series/</link>
	<description>The Math Factor Podcast Site</description>
	<lastBuildDate>Sat, 21 Nov 2009 21:45:21 -0600</lastBuildDate>
	<generator>http://wordpress.org/?v=2.8.5</generator>
	<sy:updatePeriod>hourly</sy:updatePeriod>
	<sy:updateFrequency>1</sy:updateFrequency>
		<item>
		<title>By: tricycle</title>
		<link>http://mathfactor.uark.edu/2008/08/follow-up-the-harmonic-series/comment-page-1/#comment-365</link>
		<dc:creator>tricycle</dc:creator>
		<pubDate>Thu, 21 Aug 2008 22:02:01 +0000</pubDate>
		<guid isPermaLink="false">http://mathfactor.uark.edu/?p=245#comment-365</guid>
		<description>It seems to me that a natural assumption would be that when the rope is stretched, that it is stretched uniformly. The discussion seems to assume that only the part stretched is  the rope in front of the worm with the position of the worm being fixed, i.e., after the rope is stretched to 2 m the worm is still at 1 cm instead of being proportionally stretched to 2 cm. Taking into account this additional boost leads to the recursive position at the start of each second: p(0) = 0 and p(n) = (p(n-1)+1)(n+1)/n with the length of the rope l(n) = 100(n+1) where all of the units are cm. Is there a nice closed form for this recursion?</description>
		<content:encoded><![CDATA[<p>It seems to me that a natural assumption would be that when the rope is stretched, that it is stretched uniformly. The discussion seems to assume that only the part stretched is  the rope in front of the worm with the position of the worm being fixed, i.e., after the rope is stretched to 2 m the worm is still at 1 cm instead of being proportionally stretched to 2 cm. Taking into account this additional boost leads to the recursive position at the start of each second: p(0) = 0 and p(n) = (p(n-1)+1)(n+1)/n with the length of the rope l(n) = 100(n+1) where all of the units are cm. Is there a nice closed form for this recursion?</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: strauss</title>
		<link>http://mathfactor.uark.edu/2008/08/follow-up-the-harmonic-series/comment-page-1/#comment-362</link>
		<dc:creator>strauss</dc:creator>
		<pubDate>Sun, 17 Aug 2008 18:49:00 +0000</pubDate>
		<guid isPermaLink="false">http://mathfactor.uark.edu/?p=245#comment-362</guid>
		<description>Incidentally, our post &lt;a href=&quot;http://mathfactor.uark.edu/2006/11/10/an-astronomical-cost/&quot; rel=&quot;nofollow&quot;&gt;BM. An astronomical cost!&lt;/a&gt; also involves the harmonic series and some close relatives. This is how I was able to make rough estimates of the number of bananas required, without using a calculator!</description>
		<content:encoded><![CDATA[<p>Incidentally, our post <a href="http://mathfactor.uark.edu/2006/11/10/an-astronomical-cost/" rel="nofollow">BM. An astronomical cost!</a> also involves the harmonic series and some close relatives. This is how I was able to make rough estimates of the number of bananas required, without using a calculator!</p>
]]></content:encoded>
	</item>
</channel>
</rss>
