CA. Cut the Cake!
How to satisfy the most jealous of triplets?
How to satisfy the most jealous of triplets?
Twenty three people split into two teams of eleven & one ref; no matter how they split, the teams have the same total weight! Can the players themselves be different weights?
A short, but tricky puzzle: how many guests must you invite before you can be sure that there are at least three mutual acquaintances or three mutual strangers?
Dozens of listeners sent us solutions, mercifully freeing us from this 50x50x50' box.
This puzzle has us stumped! How do you escape this diabolical trap?
Dennis Shasha answers his puzzle.
Dennis Shasha, author of the “Puzzler's Elusion” gives us a new puzzle.
The solution to last week’s question, and a very easy puzzle.